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(C) In a single-slit diffraction experiment,the condition for the first minima on either side of the central maximum is given by $d \sin 	heta = \pm

Vedclass · Accepted Answer

$\frac{2\lambda}{d}$

Vedclass · Answer

(C) In a single-slit diffraction experiment,the condition for the first minima on either side of the central maximum is given by $d \sin 	heta = \pm n\lambda$. For the first minimum $(n = 1)$,we have $d \sin 	heta = \lambda$. Since $	heta$ is very small,$\sin 	heta \approx 	heta$. Therefore,$	heta = \frac{\lambda}{d}$. The angular width of the central maximum is the distance between the first minima on both sides,which is $2	heta$. Thus,the angular width $= 2 	imes \frac{\lambda}{d} = \frac{2\lambda}{d}$.

$A$ slit of width $d$ is illuminated by light of wavelength $\lambda$. The angular width of the central maximum is:

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