What is the sum of all integers between 81 an | vedclass

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Question

(B) The integers between $81$ and $719$ that are divisible by $5$ form an arithmetic progression ($A$.$P$.).The first term $a = 85$ and the last term

Vedclass · Accepted Answer

$50800$

Vedclass · Answer

(B) The integers between $81$ and $719$ that are divisible by $5$ form an arithmetic progression ($A$.$P$.).The first term $a = 85$ and the last term $l = 715$.The common difference $d = 5$.Using the formula for the $n$-th term of an $A$.$P$.,$a_n = a + (n - 1)d$,we have:$715 = 85 + (n - 1)5$$630 = (n - 1)5$$n - 1 = 126$$n = 127$.The sum of an $A$.$P$. is given by $S_n = \frac{n}{2}(a + l)$.$S_{127} = \frac{127}{2}(85 + 715)$$S_{127} = \frac{127}{2}(800)$$S_{127} = 127 	imes 400 = 50800$.Thus,the correct option is $B$.

What is the sum of all integers between $81$ and $719$ that are divisible by $5$?

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