Medium
If $\binom{n-1}{4}, \binom{n-1}{5}$ and $\binom{n-1}{6}$ are in Arithmetic Progression,then find the relation.
- A$\binom{n+1}{6} = 2\binom{n-1}{5}$
- B$2\binom{n+1}{6} = \binom{n-1}{5}$
- C$\binom{n+1}{6} = 4\binom{n-1}{5}$
- D$4\binom{n+1}{6} = \binom{n-1}{5}$
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