If $\vec{u} = \vec{a} - \vec{b}$ and $\vec{v} = \vec{a} + \vec{b}$ and $|\vec{a}| = |\vec{b}| = 2$,then $|\vec{u} \times \vec{v}| = ......$

  • A
    $2 \sqrt{16 - (\vec{a} \cdot \vec{b})^2}$
  • B
    $\sqrt{16 - (\vec{a} \cdot \vec{b})^2}$
  • C
    $2 \sqrt{4 - (\vec{a} \cdot \vec{b})^2}$
  • D
    $\sqrt{4 - (\vec{a} \cdot \vec{b})^2}$

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Let $\vec{a}$ and $\vec{b}$ be the vectors along the diagonals of a parallelogram having area $2 \sqrt{2}$. Let the angle between $\vec{a}$ and $\vec{b}$ be acute. Given $|\vec{a}|=1$ and $|\vec{a} \cdot \vec{b}|=|\vec{a} \times \vec{b}|$. If $\vec{c}=2 \sqrt{2}(\vec{a} \times \vec{b})-2 \vec{b}$,then find the angle between $\vec{b}$ and $\vec{c}$.

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