If theta is the angle between the vectors vec | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for the sine of the angle $	heta$ between two vectors $\vec{a}$ and $\vec{b}$ is given by $\sin 	heta = \frac{|\vec{a} 	imes \vec{b

Vedclass · Accepted Answer

$5/(2\sqrt{7})$

Vedclass · Answer

(C) The formula for the sine of the angle $	heta$ between two vectors $\vec{a}$ and $\vec{b}$ is given by $\sin 	heta = \frac{|\vec{a} 	imes \vec{b}|}{|\vec{a}| |\vec{b}|}$.First,calculate the cross product $\vec{a} 	imes \vec{b}$:$\vec{a} 	imes \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \ 1 & -2 & 3 \ 2 & 1 & 1 \end{vmatrix} = \hat{i}(-2 - 3) - \hat{j}(1 - 6) + \hat{k}(1 - (-4)) = -5\hat{i} + 5\hat{j} + 5\hat{k}$.Next,find the magnitude of the cross product:$|\vec{a} 	imes \vec{b}| = \sqrt{(-5)^2 + 5^2 + 5^2} = \sqrt{25 + 25 + 25} = \sqrt{75} = 5\sqrt{3}$.Now,find the magnitudes of vectors $\vec{a}$ and $\vec{b}$:$|\vec{a}| = \sqrt{1^2 + (-2)^2 + 3^2} = \sqrt{1 + 4 + 9} = \sqrt{14}$.$|\vec{b}| = \sqrt{2^2 + 1^2 + 1^2} = \sqrt{4 + 1 + 1} = \sqrt{6}$.Finally,substitute these values into the formula:$\sin 	heta = \frac{5\sqrt{3}}{\sqrt{14} \cdot \sqrt{6}} = \frac{5\sqrt{3}}{\sqrt{84}} = \frac{5\sqrt{3}}{2\sqrt{21}} = \frac{5\sqrt{3}}{2\sqrt{7}\sqrt{3}} = \frac{5}{2\sqrt{7}}$.

If $\theta$ is the angle between the vectors $\vec{a} = \hat{i} - 2\hat{j} + 3\hat{k}$ and $\vec{b} = 2\hat{i} + \hat{j} + \hat{k}$,find the value of $\sin \theta$.

Similar Questions

If $a = 2i + 4j - 5k$ and $b = i + 2j + 3k$,then $|a \times b|$ is

$A$ unit vector perpendicular to the plane determined by the points $P(1, -1, 2)$,$Q(2, 0, -1)$,and $R(0, 2, 1)$ is:

Let $|\vec{a}|=2, |\vec{b}|=3$ and the angle between the vectors $\vec{a}$ and $\vec{b}$ be $\frac{\pi}{4}$. Then $|(\vec{a}+2 \vec{b}) \times(2 \vec{a}-3 \vec{b})|^2$ is equal to

The area of a parallelogram whose diagonals are the vectors $2 \bar{a}-\bar{b}$ and $4 \bar{a}-5 \bar{b}$,where $\bar{a}$ and $\bar{b}$ are unit vectors forming an angle of $45^{\circ}$ is

For any vector $\vec{a} \in \mathbb{R}^3$,$|\vec{a} \times \hat{i}|^2 + |\vec{a} \times \hat{j}|^2 + |\vec{a} \times \hat{k}|^2 = $ . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module