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(C) Let the position vectors of points $A, B, C$ be $\vec{a}, \vec{b}, \vec{c}$ respectively.Since $D$ is the midpoint of $BC$,its position vector $\v

Vedclass · Accepted Answer

$\frac{\vec{b} + \vec{c} - 2\vec{a}}{2}$

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(C) Let the position vectors of points $A, B, C$ be $\vec{a}, \vec{b}, \vec{c}$ respectively.Since $D$ is the midpoint of $BC$,its position vector $\vec{d}$ is given by:$\vec{d} = \frac{\vec{b} + \vec{c}}{2}$Now,the vector $\vec{AD}$ is given by the difference of the position vectors of $D$ and $A$:$\vec{AD} = \vec{d} - \vec{a}$$\vec{AD} = \frac{\vec{b} + \vec{c}}{2} - \vec{a}$$\vec{AD} = \frac{\vec{b} + \vec{c} - 2\vec{a}}{2}$

If $\vec{a}, \vec{b}, \vec{c}$ are the position vectors of points $A, B, C$ respectively,and $D$ is the midpoint of $BC$,then $\vec{AD} = \dots$

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