If $ab = 0$,write the contrapositive of the statement $(a = 0 \text{ or } b = 0)$.

  • A
    If $(a \neq 0 \text{ or } b \neq 0)$,then $ab \neq 0$
  • B
    If $ab \neq 0$,then $(a \neq 0 \text{ or } b \neq 0)$
  • C
    If $(a \neq 0 \text{ and } b \neq 0)$,then $ab \neq 0$
  • D
    If $(a = 0 \text{ and } b = 0)$,then $ab \neq 0$

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The correct logical equivalences from the following are:
$(I)$ $p \to (q \to r) \equiv (p \land q) \to r$
$(II)$ $(p \to q) \to r \equiv p \to (q \lor r)$
$(III)$ $(p \to q) \to r \equiv (p \to r) \land (\sim q \to r)$
$(IV)$ $p \to (q \to r) \equiv q \to (p \to r)$

If the truth value of the compound statement $[(p \vee q) \wedge (q \to r) \wedge (\sim r)] \to (p \wedge q)$ is $False$, then the truth values of $p \to q$ and $q \to p$ are respectively......

Which of the following is equivalent to the Boolean expression $p \wedge \sim q$?

$(\sim (\sim p)) \wedge q$ is equal to .........

$(p \wedge \sim q) \wedge (\sim p \vee q)$ is :-

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