The vertices of a regular tetrahedron are marked $1, 2, 3, 4$. If three such tetrahedra are thrown simultaneously,what is the probability that the sum of the numbers on the faces is $5$?
- A$\frac{5}{24}$
- B$\frac{5}{64}$
- C$\frac{3}{32}$
- D$\frac{3}{16}$
Explore More
Similar Questions
If $A$ is a sure event,then the value of $P(\text{not } A)$ is:
Medium
View SolutionWhen two dice are thrown simultaneously,find the probability of the following:
$(1)$ The numbers are the same.
$(2)$ The difference between the numbers is $1$.
$(1)$ The numbers are the same.
$(2)$ The difference between the numbers is $1$.
Medium
View Solution$A$ die is loaded such that the probability of throwing the number $i$ is proportional to its reciprocal. Then the probability that $3$ appears in a single throw is
If any four numbers are selected,what is the probability that the last digit of their product will be $1, 3, 5$ or $7$?
Easy
View Solution$A$ die has two faces each with number $1$,three faces each with number $2$,and one face with number $3$. If the die is rolled once,then $P(1 \text{ or } 3)$ is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo