A container holds two balls. Both balls are b | vedclass

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(C) Initially,the container has $2$ black balls. After adding $1$ white ball,the total number of balls in the container becomes $2 + 1 = 3$. The compo

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$1/3$

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(C) Initially,the container has $2$ black balls. After adding $1$ white ball,the total number of balls in the container becomes $2 + 1 = 3$. The composition of the container is now $2$ black balls and $1$ white ball. The probability $P$ of drawing a white ball is given by the ratio of the number of white balls to the total number of balls. $P(	ext{white}) = \frac{	ext{Number of white balls}}{	ext{Total number of balls}} = \frac{1}{3}$.

$A$ container holds two balls. Both balls are black. If one white ball is added to the container and then one ball is drawn at random from the container,what is the probability that it is white?

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