When a die is thrown,let event A be getting a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The sample space $S = \{1, 2, 3, 4, 5, 6\}$,so $n(S) = 6$.Event $A$ is getting a number greater than $3$,so $A = \{4, 5, 6\}$ and $n(A) = 3$.Event

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(C) The sample space $S = \{1, 2, 3, 4, 5, 6\}$,so $n(S) = 6$.Event $A$ is getting a number greater than $3$,so $A = \{4, 5, 6\}$ and $n(A) = 3$.Event $B$ is getting a number less than $5$,so $B = \{1, 2, 3, 4\}$ and $n(B) = 4$.The intersection $A \cap B$ is the set of numbers that are both greater than $3$ and less than $5$,so $A \cap B = \{4\}$ and $n(A \cap B) = 1$.The union $A \cup B$ is the set of numbers that are either in $A$ or in $B$,so $A \cup B = \{1, 2, 3, 4, 5, 6\}$ and $n(A \cup B) = 6$.Therefore,$P(A \cup B) = \frac{n(A \cup B)}{n(S)} = \frac{6}{6} = 1$.

When a die is thrown,let event $A$ be getting a number greater than $3$,and let event $B$ be getting a number less than $5$. What is $P(A \cup B)$?

Similar Questions

Let $A$ and $B$ be events for which $P(A) = x$,$P(B) = y$,and $P(A \cap B) = z$. Then $P(\bar{A} \cap B)$ equals:

Suppose $A$ and $B$ are two events such that $P(A \cap B) = \frac{3}{25}$ and $P(B - A) = \frac{8}{25}$. Then, $P(B)$ is equal to

$A$ die is thrown. Find the probability of the following event: $A$ number more than $6$ will appear.

The probability of obtaining an even prime number on each die when a pair of dice is rolled is

If $A$ and $B$ are two events such that $P(A) = \frac{1}{4}$,$P(B) = \frac{1}{2}$,and $P(A \cap B) = \frac{1}{8}$,find $P(\text{not } A \text{ and not } B)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module