The probability of failing in Physics is 20%, | vedclass

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(A) Let $P(A)$ be the probability of failing in Physics and $P(B)$ be the probability of failing in Mathematics.Given $P(A) = 20\% = 0.2$ and $P(B) =

Vedclass · Accepted Answer

$28$

Vedclass · Answer

(A) Let $P(A)$ be the probability of failing in Physics and $P(B)$ be the probability of failing in Mathematics.Given $P(A) = 20\% = 0.2$ and $P(B) = 10\% = 0.1$.Assuming the events are independent,the probability of failing in at least one subject is given by $P(A \cup B) = P(A) + P(B) - P(A \cap B)$.Since the events are independent,$P(A \cap B) = P(A) 	imes P(B) = 0.2 	imes 0.1 = 0.02$.Therefore,$P(A \cup B) = 0.2 + 0.1 - 0.02 = 0.3 - 0.02 = 0.28$.Converting to percentage,$0.28 	imes 100 = 28\%$.

The probability of failing in Physics is $20\%$,and the probability of failing in Mathematics is $10\%$. What is the probability of failing in at least one subject (in $\%$)?

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