When two dice are rolled,what is the probabil | vedclass

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(C) The total number of possible outcomes when two dice are rolled is $6^2 = 36$. The sums that are multiples of $4$ are $4, 8,$ and $12$. The pairs $

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$1/4$

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(C) The total number of possible outcomes when two dice are rolled is $6^2 = 36$. The sums that are multiples of $4$ are $4, 8,$ and $12$. The pairs $(x, y)$ that result in these sums are: For sum $= 4$: $(1, 3), (2, 2), (3, 1)$ For sum $= 8$: $(2, 6), (3, 5), (4, 4), (5, 3), (6, 2)$ For sum $= 12$: $(6, 6)$ Counting these,we have $3 + 5 + 1 = 9$ favorable outcomes. The required probability is $P = \frac{9}{36} = \frac{1}{4}$.

When two dice are rolled,what is the probability that the sum of the numbers on the faces is a multiple of $4$?

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