Find the mean deviation about the mean for th | vedclass

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(B) First,calculate the mean $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$.      $x_i$    $f_i$    $f_i x_i$    $|x_i - \bar{x}|$    $f_i |x_i - \bar{x}|$

Vedclass · Accepted Answer

$7.09$

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(B) First,calculate the mean $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$.      $x_i$    $f_i$    $f_i x_i$    $|x_i - \bar{x}|$    $f_i |x_i - \bar{x}|$        $3$    $8$    $24$    $|3 - 15| = 12$    $96$        $9$    $10$    $90$    $|9 - 15| = 6$    $60$        $17$    $12$    $204$    $|17 - 15| = 2$    $24$        $23$    $9$    $207$    $|23 - 15| = 8$    $72$        $27$    $5$    $135$    $|27 - 15| = 12$    $60$        Total    $N = 44$    $\sum f_i x_i = 660$    -    $\sum f_i |x_i - \bar{x}| = 312$  Mean $\bar{x} = \frac{660}{44} = 15$.Mean deviation about mean $= \frac{\sum f_i |x_i - \bar{x}|}{N} = \frac{312}{44} \approx 7.09$.

$x$	$10$	$11$	$12$	$13$
$f$	$6$	$12$	$18$	$12$

Find the mean deviation about the mean for the following data:

$x_i$ $3$ $9$ $17$ $23$ $27$

$f_i$ $8$ $10$ $12$ $9$ $5$

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The mean deviation about the mean for the following data is:
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The mean deviation from the median is

The mean and variance of $10$ observations are $9$ and $34.2$, respectively. If $8$ of these observations are $2, 3, 5, 10, 11, 13, 15, 21$, then the mean deviation about the median of all the $10$ observations is

Let the mean and the standard deviation of the observations $2, 3, 3, 4, 5, 7, a, b$ be $4$ and $\sqrt{2}$ respectively. Then the mean deviation about the mode of these observations is:

The mean deviation from the median for the following data is:
$x$ $10$ $11$ $12$ $13$
$f$ $6$ $12$ $18$ $12$

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Find the mean deviation about the mean for the following data: $x_i$ $3$ $9$ $17$ $23$ $27$ $f_i$ $8$ $10$ $12$ $9$ $5$