If the mode of a distribution is $18$ and the mean is $24$,then what is the median?

For a discrete series (where all values are not equal),what is the relationship between Mean Deviation $(M.D.)$,Mean $(Mean)$,and Standard Deviation $(S.D.)$?

Karl Pearson's coefficient of skewness of a distribution is $0.32$. Its standard deviation $(S.D.)$ is $6.5$ and the mean is $39.6$. The median of the distribution is:

For a normal distribution,if the mean is $M$,mode is $M_0$,and median is $M_d$,then:

Let $a_1, a_2, \dots, a_{101}$ be a group of real numbers such that $a_i > a_{i+1}$ for all values of $i$ and the mean square deviation of the group is minimum about the number $a_{51}$. Then the mode of the group will be:

In a frequency distribution,if the mean and median are $21$ and $22$ respectively,then what is the approximate mode?