For a distribution $x_1, x_2, \dots, x_{101}$ such that $x_1 < x_2 < x_3 < \dots < x_{100} < x_{101}$,the mean deviation of this distribution about a number $k$ is minimum. Then $k$ is equal to which of the following?
- A$x_1$
- B$x_{51}$
- C$x_{50}$
- D$\frac{x_1 + x_2 + \dots + x_{101}}{101}$
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Similar Questions
The average age of a teacher and three students is $20$ years. If all the students are of the same age and the difference between the teacher's age and the age of one of the students is $20$ years,find the teacher's age in years.
Medium
View SolutionThe relation between the median $M$,the second quartile ${Q_2}$,the fifth decile ${D_5}$,and the $50^{th}$ percentile ${P_{50}}$ of a set of observations is:
If for some positive $x \in R$,the frequency distribution of the marks obtained by $20$ students in a certain test is as follows:
Marks $2$ $3$ $5$ $7$ Frequency $(x+1)^2$ $2x-5$ $x^2-3x$ $x$
Then the mean of the marks is:
| Marks | $2$ | $3$ | $5$ | $7$ |
|---|---|---|---|---|
| Frequency | $(x+1)^2$ | $2x-5$ | $x^2-3x$ | $x$ |
Then the mean of the marks is:
The median of $10, 14, 11, 9, 8, 12, 6$ is
Easy
View SolutionThe mean of a set of $n$ numbers,when each is divided by $5$,is $\frac{X}{5}$. What is the mean of the original $n$ numbers?
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