(D) According to Einstein's photoelectric equation: $h\nu = e V_0 + \phi$,where $\phi$ is the work function.This can be written as: $\frac{hc}{\lambda

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(D) According to Einstein's photoelectric equation: $h\nu = e V_0 + \phi$,where $\phi$ is the work function.This can be written as: $\frac{hc}{\lambda} = e V_0 + \phi$ --- $(i)$For the second source: $\frac{hc}{\lambda'} = e V'_0 + \phi$ --- (ii)Subtracting equation $(i)$ from (ii):$e(V'_0 - V_0) = hc \left( \frac{1}{\lambda'} - \frac{1}{\lambda} \right)$Using $hc \approx 12400 \ eV \cdot \mathring{A}$:$V'_0 - V_0 = \frac{12400}{4272} - \frac{12400}{6402} \approx 2.902 - 1.937 = 0.965 \ V$$V'_0 = 0.965 + 0.54 = 1.505 \ V \approx 1.51 \ V$.

Class 12 Physics Dual Nature of Radiation and matter Einstein's Photoelectric Equation and Energy Quantum of Radiation

Difficult

$A$ photosensitive surface made of cesium on tungsten is irradiated by monochromatic radiation of wavelength $640.2 \ nm$ $(1 \ nm = 10^{-9} \ m)$ from a neon bulb. The measured stopping potential is $0.54 \ V$. If the source is replaced by another source and the same photocell is irradiated by a line of $427.2 \ nm$,what will be the new stopping potential in $V$?

A
$2.10$
B
$0.90$
C
$1.80$
D
$1.51$

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Class 12

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Dual Nature of Radiation and matter

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Einstein's Photoelectric Equation and Energy Quantum of Radiation

Mercury violet light $(\lambda = 4558 \mathring{A})$ is falling on a photosensitive material $(\phi = 2.5 \text{ eV})$. The speed of the ejected electrons is,in $\text{m/s}$,about:

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By the photoelectric effect,Einstein proved:

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If the frequency of light in a photoelectric experiment is doubled,the stopping potential will

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Two identical photocathodes receive light of frequencies $f_{1}$ and $f_{2}$ respectively. If the velocities of the photo-electrons emitted are $v_{1}$ and $v_{2}$ respectively,then:

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At an incident radiation frequency of $v_1$,which is greater than the threshold frequency,the stopping potential for a certain metal is $V_1$. At frequency $2 v_1$,the stopping potential is $3 V_1$. If the stopping potential at frequency $4 v_1$ is $n V_1$,then $n$ is

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