The ratio of energies of photons with wavelen | vedclass

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(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Since $h$ (Planck's constant) and $c$ (speed of light) are constants,the e

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$2$

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(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Since $h$ (Planck's constant) and $c$ (speed of light) are constants,the energy $E$ is inversely proportional to the wavelength $\lambda$,i.e.,$E \propto \frac{1}{\lambda}$.Therefore,the ratio of the energies is given by $\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1}$.Substituting the given values: $\frac{E_1}{E_2} = \frac{300 \ nm}{150 \ nm} = 2$.Thus,the ratio is $2:1$ or simply $2$.

The ratio of energies of photons with wavelengths $\lambda_1 = 150 \ nm$ and $\lambda_2 = 300 \ nm$ is:

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