The anode voltage of a photocell is kept cons | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the photoelectric effect, the photoelectric current $(I)$ depends on the intensity of the incident light, provided the frequency of the inciden

Vedclass · Accepted Answer

Vedclass · Answer

(B) In the photoelectric effect, the photoelectric current $(I)$ depends on the intensity of the incident light, provided the frequency of the incident light is greater than the threshold frequency $(
u > 
u_0)$.The threshold frequency $(
u_0)$ corresponds to a threshold wavelength $(\lambda_0 = c / 
u_0)$.If the wavelength of the incident light $(\lambda)$ is greater than the threshold wavelength $(\lambda_0)$, no photoelectric emission occurs, and the current $(I)$ is zero.If the wavelength $(\lambda)$ is less than or equal to the threshold wavelength $(\lambda_0)$, photoelectric emission occurs. Assuming the intensity of the incident light remains constant as the wavelength is varied, the photoelectric current $(I)$ remains constant for all $\lambda \le \lambda_0$.Therefore, the graph of photoelectric current $(I)$ versus wavelength $(\lambda)$ shows zero current for $\lambda > \lambda_0$ and a constant current for $\lambda \le \lambda_0$. This corresponds to the graph shown in option $(B)$.

The anode voltage of a photocell is kept constant. The wavelength of the light incident on the cathode is changed gradually. Which of the following graphs represents the variation of the photoelectric current $(I)$ with the wavelength $(\lambda)$?

Similar Questions

Assertion: The specific charge of positive rays is not constant.
Reason: The mass of ions varies with speed.

Two electrons are moving with the same speed $v$. One electron enters a region of a uniform electric field,while the other enters a region of a uniform magnetic field. If the de-Broglie wavelengths of the two electrons after some time are ${\lambda _1}$ and ${\lambda _2}$ respectively,then:

An electromagnetic wave of wavelength $\lambda$ is incident on a photosensitive surface of negligible work function. If the photoelectrons emitted from this surface have the de-Broglie wavelength $\lambda_{1}$,then:

An electron is moving through a field. It is moving $(i)$ opposite to an electric field and $(ii)$ perpendicular to a magnetic field as shown. For each situation,determine the de-Broglie wavelength of the electron.

The anode voltage of a photocell is kept fixed. The wavelength $\lambda$ of the light falling on the cathode is gradually changed. The plate current $I$ of the photocell varies as follows:

Vedclass Test Series

Exam Paper Generator

Online Exam Module