If f_1, f_2,and f_3 are the frequencies of K_ | vedclass

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Question

(C) The $K_\alpha$ $X$-ray is produced by an electron transition from the $L$ shell $(n=2)$ to the $K$ shell $(n=1)$. Its energy is $hf_1 = E_L - E_K$

Vedclass · Accepted Answer

$f_2 = f_1 + f_3$

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(C) The $K_\alpha$ $X$-ray is produced by an electron transition from the $L$ shell $(n=2)$ to the $K$ shell $(n=1)$. Its energy is $hf_1 = E_L - E_K$.The $K_\beta$ $X$-ray is produced by an electron transition from the $M$ shell $(n=3)$ to the $K$ shell $(n=1)$. Its energy is $hf_2 = E_M - E_K$.The $L_\alpha$ $X$-ray is produced by an electron transition from the $M$ shell $(n=3)$ to the $L$ shell $(n=2)$. Its energy is $hf_3 = E_M - E_L$.From the energy levels,we can see that: $(E_M - E_K) = (E_M - E_L) + (E_L - E_K)$.Substituting the energy expressions: $hf_2 = hf_3 + hf_1$.Dividing by $h$,we get: $f_2 = f_1 + f_3$.

If $f_1, f_2$,and $f_3$ are the frequencies of $K_\alpha, K_\beta$,and $L_\alpha$ $X$-rays of a given metal,respectively,then:

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