The slope of the graph between stopping potential and the frequency of incident radiation for the photoelectric effect is . . . . . . .

  • A
    $h/e$
  • B
    $he$
  • C
    $e/h$
  • D
    None of these.

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Similar Questions

$A$ certain metallic surface is illuminated with monochromatic light of wavelength $\lambda$. The stopping potential for the photoelectric current for this light is $3V_0$. If the same surface is illuminated with light of wavelength $2\lambda$,the stopping potential is $V_0$. The threshold wavelength for this surface for the photoelectric effect is:

When light is incident on a surface,photoelectrons are emitted. For these photoelectrons:

The photoelectric work function for a metal is $2.4 \ eV$. Among the four wavelengths,the wavelength of light for which photoemission does not take place is: (in $nm$)

In an experiment on the photoelectric effect,the wavelength of the incident radiation is $\lambda$. The wavelength of the incident radiation is reduced to $\frac{1}{3}$ of the initial value,and the maximum kinetic energy of the photoelectron is observed to be $n$ times the previous value. The threshold wavelength for the metal plate is:

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The kinetic energy with which electrons are emitted from a metal surface due to the photoelectric effect is:

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