Find the number of photons emitted per second | vedclass

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(A) Given: Power $P = 100\, W$,Wavelength $\lambda = 694\, nm = 694 	imes 10^{-9}\, m$.Energy of one photon $E = \frac{hc}{\lambda}$.The number of ph

Vedclass · Accepted Answer

$3.49 	imes 10^{20}$

Vedclass · Answer

(A) Given: Power $P = 100\, W$,Wavelength $\lambda = 694\, nm = 694 	imes 10^{-9}\, m$.Energy of one photon $E = \frac{hc}{\lambda}$.The number of photons emitted per second $n$ is given by $n = \frac{P}{E} = \frac{P\lambda}{hc}$.Substituting the values: $h = 6.63 	imes 10^{-34}\, J\cdot s$,$c = 3 	imes 10^8\, m/s$.$n = \frac{100 	imes 694 	imes 10^{-9}}{6.63 	imes 10^{-34} 	imes 3 	imes 10^8}$.$n = \frac{69400 	imes 10^{-9}}{19.89 	imes 10^{-26}} \approx 3489.19 	imes 10^{17} \approx 3.49 	imes 10^{20}$ photons/second.

Find the number of photons emitted per second by a $100\, W$ red light source. Assume for simplicity that the average wavelength of each photon is $694\, nm$.

Similar Questions

The energy of a photon with a wavelength of $\lambda = 4000 \ \mathring{A}$ is equal to ........ Joules.

If the energy of a photon corresponding to a wavelength of $6000 \mathring{A}$ is $3.2 \times 10^{-19} \ J$,the photon energy for a wavelength of $4000 \mathring{A}$ will be . . . . . . .

The frequency of a photon having energy $100 \ eV$ is $(h = 6.6 \times 10^{-34} \ J \cdot s)$.

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Write the equation for the energy of a photon.

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