The graph of relative intensity versus wavele | vedclass

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Question

(B) According to Wien's displacement law,the wavelength corresponding to maximum intensity $\lambda_m$ is inversely proportional to the absolute tempe

Vedclass · Accepted Answer

$T_1 > T_3 > T_2$

Vedclass · Answer

(B) According to Wien's displacement law,the wavelength corresponding to maximum intensity $\lambda_m$ is inversely proportional to the absolute temperature $T$,i.e.,$\lambda_m \propto \frac{1}{T}$.From the given graph,we can observe the wavelengths corresponding to the peak intensities for the three temperatures:$\lambda_{m1} Since $\lambda_m \propto \frac{1}{T}$,a smaller wavelength corresponds to a higher temperature.Therefore,the relationship between the temperatures is $T_1 > T_3 > T_2$.

The graph of relative intensity versus wavelength for three perfectly black bodies at temperatures $T_1, T_2,$ and $T_3$ is shown below. The relationship between their temperatures is:

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