In an electromagnetic wave,the electric field $\vec{E}$ and the magnetic field $\vec{B}$ oscillate in the region near the source as:
- AParallel to each other and in the same phase
- BPerpendicular to each other and in the same phase
- CParallel to each other and with a phase difference of $\pi / 2$
- DPerpendicular to each other and with a phase difference of $\pi / 2$
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$A$ plane electromagnetic wave of frequency $20 \ MHz$ travels in free space along the $+x$ direction. At a particular point in space and time, the electric field vector of the wave is $E_y = 9.3 \ Vm^{-1}$. Then, the magnetic field vector of the wave at that point is:
The electric field part of an electromagnetic wave in a medium is represented by:
$E_x = 0;$
$E_y = 2.5 \, \text{N/C} \cos \left[ \left( 2\pi \times 10^6 \, \text{rad/s} \right) t - \left( \pi \times 10^{-2} \, \text{rad/m} \right) x \right];$
$E_z = 0.$
The wave is:
$E_x = 0;$
$E_y = 2.5 \, \text{N/C} \cos \left[ \left( 2\pi \times 10^6 \, \text{rad/s} \right) t - \left( \pi \times 10^{-2} \, \text{rad/m} \right) x \right];$
$E_z = 0.$
The wave is:
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View SolutionWhat do electromagnetic waves $NOT$ transport?
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View SolutionThe amplitude of the electric field associated with a light beam of intensity $\frac{15}{\pi} \text{ W m}^{-2}$ is (in $\text{ N C}^{-1}$)
An electromagnetic wave with frequency $\omega$ and wavelength $\lambda$ travels in the $+y$ direction. Its magnetic field is along the $+x$ axis. The vector equation for the associated electric field (of amplitude $E_0$) is:
MediumAIEEE 2012
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