At a given temperature,the density of gas x i | vedclass

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(C) From the ideal gas equation,$PV = nRT$,we know that $PM = dRT$,where $P$ is pressure,$M$ is molar mass,$d$ is density,$R$ is the gas constant,and

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$P_x / P_y = 6$

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(C) From the ideal gas equation,$PV = nRT$,we know that $PM = dRT$,where $P$ is pressure,$M$ is molar mass,$d$ is density,$R$ is the gas constant,and $T$ is temperature.For gas $x$: $P_x M_x = d_x RT$For gas $y$: $P_y M_y = d_y RT$Dividing the two equations: $\frac{P_x M_x}{P_y M_y} = \frac{d_x}{d_y}$Given: $d_x = 2d_y$ and $M_x = \frac{1}{3} M_y$Substituting these values: $\frac{P_x}{P_y} 	imes \frac{1}{3} = \frac{2d_y}{d_y} = 2$Therefore,$\frac{P_x}{P_y} = 2 	imes 3 = 6$.

At a given temperature,the density of gas $x$ is twice that of gas $y$. The molar mass of $x$ is one-third of the molar mass of $y$. What is the ratio of their pressures $(P_x / P_y)$?

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