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(B) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molecular weight $M$ of the g

Vedclass · Accepted Answer

$4:3$

Vedclass · Answer

(B) According to Graham's Law of Diffusion,the rate of diffusion $r$ is inversely proportional to the square root of the molecular weight $M$ of the gas: $r \propto \frac{1}{\sqrt{M}}$.For two gases $A$ and $B$,the ratio of their rates of diffusion is given by: $\frac{r_A}{r_B} = \sqrt{\frac{M_B}{M_A}}$.Given $M_A = 36$ and $M_B = 64$.Substituting the values: $\frac{r_A}{r_B} = \sqrt{\frac{64}{36}} = \frac{8}{6} = \frac{4}{3}$.Therefore,the ratio $r_A : r_B$ is $4:3$.

What is the ratio of the rates of diffusion of gases $A$ and $B$ having molecular weights $36$ and $64$ respectively?

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