(C) The $rms$ speed of a gas is given by the formula $u_{rms} = \sqrt{\frac{3RT}{M}}$.At $T_1 = 27\,^oC = 300\,K$,the speed is $u_1 = \sqrt{\frac{3R \

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) The $rms$ speed of a gas is given by the formula $u_{rms} = \sqrt{\frac{3RT}{M}}$.At $T_1 = 27\,^oC = 300\,K$,the speed is $u_1 = \sqrt{\frac{3R \times 300}{M}}$.At $T_2 = 927\,^oC = 1200\,K$,the speed is $u_2 = \sqrt{\frac{3R \times 1200}{M}}$.Calculating the ratio: $\frac{u_2}{u_1} = \sqrt{\frac{1200}{300}} = \sqrt{4} = 2$.Therefore,$u_2 = 2u_1$,which means the $rms$ speed becomes double the initial value.

Class 11 Chemistry States of Matter Molecular speeds

Medium

If the temperature of a gas is increased from $27\,^oC$ to $927\,^oC$,what will be the change in its $rms$ speed?

A
Same as the previous value
B
Half of the previous value
C
Double the previous value
D
Four times the previous value

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

States of Matter

Subtopic

Molecular speeds

The ratio between the $RMS$ velocity of $N_2$ at $200 \ K$ and that of $CO$ at $800 \ K$ is (molecular mass of $N_2 = 28 \ g \ mol^{-1}$, molecular mass of $CO = 28 \ g \ mol^{-1}$)

EasyTS EAMCET 2018

View Solution

At what temperature will the $rms$ speed of $N_2$ gas at $1 \, atm$ pressure be equal to the $rms$ speed of $CO_2$ at $STP$?

Medium

View Solution

The density of a gas at $100 \, kPa$ pressure is $0.1 \, g \, dm^{-3}$. The root mean square speed of the gas in $ms^{-1}$ is:

Medium

View Solution

The ratio of root mean square velocity of $H_2$ at $50 \ K$ to that of $O_2$ at $800 \ K$ is

Medium

View Solution

At $400 \ K$,the root mean square $(rms)$ speed of a gas $X$ (molecular weight $= 40$) is equal to the most probable speed of gas $Y$ at $60 \ K$. The molecular weight of the gas $Y$ is:

IIT 2009

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

If the temperature of a gas is increased from $27\,^oC$ to $927\,^oC$,what will be the change in its $rms$ speed?

Similar Questions

The ratio between the $RMS$ velocity of $N_2$ at $200 \ K$ and that of $CO$ at $800 \ K$ is (molecular mass of $N_2 = 28 \ g \ mol^{-1}$, molecular mass of $CO = 28 \ g \ mol^{-1}$)

At what temperature will the $rms$ speed of $N_2$ gas at $1 \, atm$ pressure be equal to the $rms$ speed of $CO_2$ at $STP$?

The density of a gas at $100 \, kPa$ pressure is $0.1 \, g \, dm^{-3}$. The root mean square speed of the gas in $ms^{-1}$ is:

The ratio of root mean square velocity of $H_2$ at $50 \ K$ to that of $O_2$ at $800 \ K$ is

At $400 \ K$,the root mean square $(rms)$ speed of a gas $X$ (molecular weight $= 40$) is equal to the most probable speed of gas $Y$ at $60 \ K$. The molecular weight of the gas $Y$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module