In the reaction Cr_2O_7^{2-} + X xrightarrow{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction involves the reduction of dichromate $(Cr_2O_7^{2-})$ to $Cr^{3+}$,which means $X$ must act as a reducing agent and undergo oxidation

Vedclass · Accepted Answer

$SO_4^{2-}$

Vedclass · Answer

(B) The reaction involves the reduction of dichromate $(Cr_2O_7^{2-})$ to $Cr^{3+}$,which means $X$ must act as a reducing agent and undergo oxidation.In $SO_4^{2-}$,the oxidation state of sulfur is $+6$,which is its maximum oxidation state.Therefore,$SO_4^{2-}$ cannot be oxidized further and cannot act as a reducing agent in this reaction.Thus,$SO_4^{2-}$ cannot be $X$.

In the reaction $Cr_2O_7^{2-} + X \xrightarrow{H^+} Cr^{3+} + H_2O + \text{Oxidized product of } X$,which of the following cannot be $X$?

Similar Questions

Which is a mild oxidising agent?

Which substance is serving as a reducing agent in the following reaction: $14H^{+} + Cr_2O_7^{2-} + 3Ni \to 2Cr^{3+} + 7H_2O + 3Ni^{2+}$?

Which acts as an oxidising agent in the following reaction?
$2H_2O_{(l)} + 2Na_{(s)} \to 2NaOH_{(aq)} + H_{2_{(g)}}$

The main reason for the brown ring test of $NO_3^-$ is:

Which of the following cannot function as an oxidising agent?

Vedclass Test Series

Exam Paper Generator

Online Exam Module