Bubbles of gas z are evolved from a solution | vedclass

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Question

(A) The reduction potential indicates the tendency of a species to get reduced. $A$ higher reduction potential means a stronger oxidizing agent.Given

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$y$ oxidizes $z$ but not $x$.

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(A) The reduction potential indicates the tendency of a species to get reduced. $A$ higher reduction potential means a stronger oxidizing agent.Given the order of reduction potential: $x > y > z$.Since $z$ has the lowest reduction potential,it acts as the strongest reducing agent and is easily oxidized.Species with higher reduction potential can oxidize species with lower reduction potential.Therefore,$y$ (having higher reduction potential than $z$) can oxidize $z$,but $y$ cannot oxidize $x$ (as $x$ has a higher reduction potential than $y$).

Bubbles of gas $z$ are evolved from a solution containing $x$ and $y$. If the order of reduction potential is $x > y > z$,then:

Similar Questions

Standard electrode potentials are given:
$A^{+}/A = -2.93 \ V$ $B^{+}/B = 0.80 \ V$
$C^{2+}/C = -2.37 \ V$ $D^{3+}/D = -0.74 \ V$
Increasing order of reducing power of these metals:

Which of the following metals cannot displace $H_2$ from acids or $H_2O$ from its compounds?

Calculate $E_{cell}^o$ of the following galvanic cell at $298 \ K$:
$Ca_{(s)} | Ca^{2+}_{(aq)} || Fe^{2+}_{(aq)} | Fe_{(s)}$
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Given that $E^o_{K^{+}/K} = -2.93 \ V$,$E^o_{Fe^{2+}/Fe} = -0.44 \ V$,$E^o_{Zn^{2+}/Zn} = -0.76 \ V$,and $E^o_{Cu^{2+}/Cu} = 0.34 \ V$. Based on this data,which of the following is the strongest reducing agent?

Given $E_{Cu^{2+}/Cu^{+}}^o = 0.15 \, V$,$E_{Cu^{2+}/Cu}^o = 0.34 \, V$. The standard electrode potential for the half-cell $Cu^{+}/Cu$ is ............. $V$.

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