Given the limiting molar conductivities at $25^{\circ}C$ for the following electrolytes in $S \, cm^{2} \, mol^{-1}$:
$KCl = 149.9$
$KNO_{3} = 145.0$
$HCl = 426.2$
$NaOAc = 91.0$
$NaCl = 126.5$
Calculate $\Lambda^{\infty}_{HOAc}$ using the Kohlrausch law of independent migration of ions.

At a particular temperature,the ratio of molar conductance to specific conductance of $0.01 \ M$ $NaCl$ solution is

Calculate the molar conductivity of $NH_4OH$ at infinite dilution by using the following data:
$[\Lambda _m^o(NH_4Cl) = 129.8, \Lambda _m^o(KOH) = 248.0$ and $\Lambda _m^o(KCl) = 126 \ S \ cm^2 \ mol^{-1}]$

Conductivity of $0.001 \ M$ aqueous solution of $Na_2SO_4$ is found to be $2.6 \times 10^{-3} \ S \ cm^{-1}$ at $25 \ ^oC$. If limiting molar conductance of $Na^+$ is $50 \ S \ cm^2 \ mol^{-1}$,then limiting molar conductance of $SO_4^{2-}$ will be .............. $S \ cm^2 \ mol^{-1}$ (neglect conductivity of water).

If $ᴧ^{0} CH_{3}COONa = 91 \ S \ cm^{2} \ mol^{-1}$ and $ᴧ^{0} HCl = 462.2 \ S \ cm^{2} \ mol^{-1}$,then what value is required to calculate $ᴧ^{0} CH_{3}COOH$?

Resistivity of $0.5 \ M$ electrolytic solution is $10 \ \Omega \ cm$. Find the molar conductivity of the solution.