Which of the following $M$ solutions of $KCl$ has the lowest value of specific conductivity?

Molar ionic conductivities of a divalent cation and a divalent anion are $57 \ S \ cm^2 \ mol^{-1}$ and $73 \ S \ cm^2 \ mol^{-1}$ respectively. The molar conductivity of a solution of an electrolyte containing these ions will be:

$A$ conductivity cell dipped in $0.05 \ M$ $KCl$ has resistance $600 \ \Omega$. If conductivity is $0.0012 \ \Omega^{-1} \ cm^{-1}$,what is the value of cell constant (in $cm^{-1}$)?

The resistance of a conductivity cell containing $0.01 \, M \, KCl$ solution at $298 \, K$ is $1750 \, \Omega$. If the conductivity of $0.01 \, M \, KCl$ solution at $298 \, K$ is $0.152 \times 10^{-3} \, S \, cm^{-1}$,then the cell constant of the conductivity cell is $.......... \, \times 10^{-3} \, cm^{-1}$.

$0.2\% (w/v)$ solution of $NaOH$ is measured to have resistivity $870.0 \ m\Omega \ m$. The molar conductivity of the solution will be $........ \times 10^2 \ mS \ dm^2 \ mol^{-1}$. $(Nearest \ integer)$

Conductivity of a solution is $1.26 \times 10^{-2} \ \Omega^{-1} \ cm^{-1}$. Calculate molar conductivity for $0.01 \ M$ solution.