Calculate the equilibrium constant for the cell reaction at $298 \ K$: $Cu_{(s)} + 2Ag^{+}_{(aq)} \rightarrow Cu^{2+}_{(aq)} + 2Ag_{(s)}$,given $E^{0}_{cell} = 0.46 \ V$.
- A$2.0 \times 10^{10}$
- B$4.0 \times 10^{10}$
- C$4 \times 10^{15}$
- D$2.4 \times 10^{10}$
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