Equal amounts of electricity are passed throu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Faraday's second law of electrolysis,the mass of substances deposited is proportional to their equivalent weights when the same quant

Vedclass · Accepted Answer

$0.17$

Vedclass · Answer

(B) According to Faraday's second law of electrolysis,the mass of substances deposited is proportional to their equivalent weights when the same quantity of electricity is passed through different electrolytes.$\frac{W_{Ni}}{W_{Cr}} = \frac{E_{Ni}}{E_{Cr}}$Here,$W_{Ni} = 0.3 \ g$,$Atomic \ mass \ of \ Ni = 59$,$Valency \ of \ Ni = 2$,$Atomic \ mass \ of \ Cr = 52$,$Valency \ of \ Cr = 3$.Equivalent weight of $Ni$ $(E_{Ni})$ = $\frac{59}{2} = 29.5$.Equivalent weight of $Cr$ $(E_{Cr})$ = $\frac{52}{3} = 17.33$.Substituting the values: $\frac{0.3}{W_{Cr}} = \frac{29.5}{17.33}$.$W_{Cr} = \frac{0.3 	imes 17.33}{29.5} \approx 0.176 \ g$.Rounding to the nearest option,the answer is $0.17 \ g$.

List $I$ (Conversion)	List $II$ (Number of Faraday required)
$A$. $1 \text{ mol of } H_2O \text{ to } O_2$	$I$. $3F$
$B$. $1 \text{ mol of } MnO_4^- \text{ to } Mn^{2+}$	$II$. $2F$
$C$. $1.5 \text{ mol of } Ca \text{ from molten } CaCl_2$	$III$. $1F$
$D$. $1 \text{ mol of } FeO \text{ to } Fe_2O_3$	$IV$. $5F$

Similar Questions

The amount of copper metal deposited at cathode on passing electric current of $500 \ mA$ for $20 \ min$ in cupric chloride solution is ............ $g$

$A$ $4 \ A$ current is passed through a solution of zinc sulphate for $50 \ min$. Find the amount of zinc deposited at the cathode in $g$.

The atomic weight of $Fe$ is $56$. The weight of $Fe$ deposited from $FeCl_3$ solution by passing $0.6$ Faraday of electricity is $............$ $g$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module