If $\Lambda _{NaCl}^{o}=126\,S\,cm^{2}mol^{-1}$,$\Lambda _{KBr}^{o}=152\,S\,cm^{2}mol^{-1}$,and $\Lambda _{KCl}^{o}=150\,S\,cm^{2}mol^{-1}$,then find $\Lambda ^{o}_{NaBr}$ in $S\,cm^{2}mol^{-1}$.
- A$178$
- B$176$
- C$128$
- D$202$
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