The values of lambda^{infty}_m for NH_4Cl,NaO | vedclass

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(B) According to Kohlrausch's law of independent migration of ions,the limiting molar conductivity of a weak electrolyte can be calculated using the l

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$251.5$

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(B) According to Kohlrausch's law of independent migration of ions,the limiting molar conductivity of a weak electrolyte can be calculated using the limiting molar conductivities of strong electrolytes.For $NH_4OH$,the expression is: $\lambda^{\infty}_m(NH_4OH) = \lambda^{\infty}_m(NH_4Cl) + \lambda^{\infty}_m(NaOH) - \lambda^{\infty}_m(NaCl)$.Substituting the given values: $\lambda^{\infty}_m(NH_4OH) = 129.8 + 248.1 - 126.4$.$\lambda^{\infty}_m(NH_4OH) = 377.9 - 126.4 = 251.5 \ \Omega^{-1} \ cm^2 \ mol^{-1}$.

The values of $\lambda^{\infty}_m$ for $NH_4Cl$,$NaOH$,and $NaCl$ are $129.8$,$248.1$,and $126.4 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively. Calculate $\lambda^{\infty}_m$ for $NH_4OH$ solution (in $\Omega^{-1} \ cm^2 \ mol^{-1}$).

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