What is the equivalent weight of potassium pe | vedclass

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(B) In an acidic medium,$KMnO_4$ acts as an oxidizing agent and converts ferrous ions $(Fe^{2+})$ to ferric ions $(Fe^{3+})$.The reduction half-reacti

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$31.6$

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(B) In an acidic medium,$KMnO_4$ acts as an oxidizing agent and converts ferrous ions $(Fe^{2+})$ to ferric ions $(Fe^{3+})$.The reduction half-reaction for $KMnO_4$ is:$MnO_4^- + 8H^+ + 5e^- 	o Mn^{2+} + 4H_2O$The number of electrons gained ($n$-factor) per molecule of $KMnO_4$ is $5$.The molar mass of $KMnO_4$ is $39 + 55 + (4 	imes 16) = 158 \ g/mol$.Equivalent weight = $\frac{	ext{Molar mass}}{n	ext{-factor}} = \frac{158}{5} = 31.6$.

What is the equivalent weight of potassium permanganate $(KMnO_4)$ when it acts as an oxidizing agent in the conversion of ferrous ions to ferric ions in an acidic medium?

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