The bond angle in PH_3 is closest to which of | vedclass

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(A) In the corresponding compound $NH_3$,the bond angle is $107^o$.However,in $PH_3$,the bond angle is approximately $90^o$.This is because,despite ha

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$90$

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(A) In the corresponding compound $NH_3$,the bond angle is $107^o$.However,in $PH_3$,the bond angle is approximately $90^o$.This is because,despite having a similar electronic structure,the electronegativity of the central atom $(P)$ is lower than that of $N$. As a result,the bonding electrons are further from the central atom,reducing the $bp-bp$ repulsion and causing the bond angle to decrease towards $90^o$.

List-$A$	List-$B$
$(1)$ $AB_3E_2$	$(A)$ $BrF_5$
$(2)$ $AB_2E_2$	$(B)$ $NH_3$
$(3)$ $AB_5E$	$(C)$ $H_2O$
$(4)$ $AB_3E$	$(D)$ $ClF_3$

The bond angle in $PH_3$ is closest to which of the following $^o$?

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Which of the following compounds has the smallest bond angle $(X-A-X)$ in each series respectively?

$A$. $OSF_2, OSCl_2, OSBr_2$

$B$. $SbCl_3, SbBr_3, SbI_3$

$C$. $PI_3, AsI_3, SbI_3$

$A$ covalent molecule $AB_{3}$ has a pyramidal structure. The number of lone pairs and bond pairs of electrons in the molecule are respectively:

Match the following List-$A$ and List-$B$ correctly.

List-$A$ List-$B$

$(1)$ $AB_3E_2$ $(A)$ $BrF_5$

$(2)$ $AB_2E_2$ $(B)$ $NH_3$

$(3)$ $AB_5E$ $(C)$ $H_2O$

$(4)$ $AB_3E$ $(D)$ $ClF_3$

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