Which of the following is the correct decreas | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The correct decreasing order of bond angles is $NO_2^+ > NO_2 > NO_2^-$.$1$. $NO_2^+$ is a linear molecule with $sp$ hybridization and a bond angl

Vedclass · Accepted Answer

$NO_2^+ > NO_2 > NO_2^-$

Vedclass · Answer

(C) The correct decreasing order of bond angles is $NO_2^+ > NO_2 > NO_2^-$.$1$. $NO_2^+$ is a linear molecule with $sp$ hybridization and a bond angle of $180^{\circ}$. It has no lone pair on the central nitrogen atom.$2$. $NO_2$ has one unpaired electron on the nitrogen atom,which exerts less repulsion than a lone pair,resulting in a bond angle of approximately $134^{\circ}$.$3$. $NO_2^-$ has one lone pair on the nitrogen atom,which exerts strong repulsion on the bonding pairs,reducing the bond angle to approximately $115^{\circ}$.

Which of the following is the correct decreasing order of bond angles?

Similar Questions

Which of the following represents the correct increasing order of bond angles for the given species?

The shape of $BrF_5$ molecule is

Which of the following is not tetrahedral?

Two lone pairs of electrons and two bond pairs of electrons are present in

The number of molecules having a lone pair of electrons on the central atom in the following is: $BF_3, SF_4, SiCl_4, XeF_4, NCl_3, XeF_6, PCl_5, HgCl_2, SnCl_2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module