What is the correct order of bond angles (fro | vedclass

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(C) To determine the bond angles,we analyze the hybridization and the number of lone pairs on the central atom:CompoundHybridizationLone PairsBond Ang

Vedclass · Accepted Answer

$H_2S < NH_3 < SiH_4 < BF_3$

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(C) To determine the bond angles,we analyze the hybridization and the number of lone pairs on the central atom:CompoundHybridizationLone PairsBond Angle$H_2S$$sp^3$$2$$\approx 92.2^o$$NH_3$$sp^3$$1$$\approx 107^o$$SiH_4$$sp^3$$0$$109.5^o$$BF_3$$sp^2$$0$$120^o$As the number of lone pairs increases,the bond angle decreases due to increased lone pair-bond pair repulsion.Therefore,the correct order is $H_2S < NH_3 < SiH_4 < BF_3$.

List-$I$ (molecule/ion)	List-$II$ (Number of lone pairs of electrons on the central atom)
$(A)$ $XeF_2$	$(I)$ $2$
$(B)$ $XeO_3$	$(II)$ $0$
$(C)$ $XeF_4$	$(III)$ $3$
$(D)$ $PF_6^-$	$(IV)$ $1$

What is the correct order of bond angles (from smallest to largest) in $H_2S, NH_3, BF_3,$ and $SiH_4$?

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