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(A) The total number of electrons in $O_2^+$ is $15$. The molecular orbital configuration is: $KK \sigma 2s^2 \sigma^* 2s^2 \sigma 2p_z^2 \pi 2p_x^2 =

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Bond order of $2.5$

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(A) The total number of electrons in $O_2^+$ is $15$. The molecular orbital configuration is: $KK \sigma 2s^2 \sigma^* 2s^2 \sigma 2p_z^2 \pi 2p_x^2 = \pi 2p_y^2 \pi^* 2p_x^1$. Bond order is calculated as: $	ext{Bond Order} = \frac{N_b - N_a}{2} = \frac{10 - 5}{2} = 2.5$. Since it contains one unpaired electron,it is paramagnetic. The bond order of $O_2^+$ $(2.5)$ is higher than that of $O_2$ $(2.0)$,so $O_2^+$ is more stable than $O_2$.

According to the Molecular Orbital Theory,which of the following properties does the $O_2^+$ species possess?

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