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(C) According to the Molecular Orbital Theory,the bond order of a molecule is calculated as: $Bond \ Order = \frac{1}{2} (N_b - N_a)$,where $N_b$ is t

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$He_2$

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(C) According to the Molecular Orbital Theory,the bond order of a molecule is calculated as: $Bond \ Order = \frac{1}{2} (N_b - N_a)$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons.For $He_2$,the total number of electrons is $4$.The electronic configuration is: $\sigma_{1s}^2 \sigma_{1s}^{*2}$.Bond order $= \frac{2 - 2}{2} = 0$.$A$ bond order of $0$ indicates that the molecule is unstable and does not exist.

According to the Molecular Orbital Theory,which of the following does not exist?

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