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(A) The reactivity towards electrophilic substitution depends on the electron density of the benzene ring.In Aniline $(I)$,the $-NH_2$ group is a stro

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$I > II > III$

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(A) The reactivity towards electrophilic substitution depends on the electron density of the benzene ring.In Aniline $(I)$,the $-NH_2$ group is a strong electron-donating group due to its $+M$ effect,which increases electron density at the ortho and para positions,making it highly reactive.In Benzene $(II)$,there is no substituent to alter the electron density.In Nitrobenzene $(III)$,the $-NO_2$ group is a strong electron-withdrawing group due to both $-I$ and $-M$ effects,which significantly decreases the electron density of the ring,making it the least reactive.Therefore,the order of reactivity is $I > II > III$.

Arrange the following compounds in the decreasing order of their reactivity towards electrophilic substitution reaction: Aniline $(I)$,Benzene $(II)$,and Nitrobenzene $(III)$.

Similar Questions

Which of the following is most reactive towards nitration?

Assertion : Nitrating mixture used for carrying out nitration of benzene consists of conc. $HNO_3 +$ conc. $H_2SO_4$.
Reason : In presence of $H_2SO_4$,$HNO_3$ acts as a base and produces $NO_2^+$ ions.

In the below mentioned compounds,the decreasing order of reactivity towards electrophilic substitution is:

$ClCH_2-CH_2Cl$ $\xrightarrow[(ii) NaNH_2]{(i) Alc. KOH}$ $A$ $\xrightarrow{\text{Red hot Fe tube}}$ $B$
Identify product $B$ in the above reaction sequence.

Among $P$,$Q$,$R$ and $S$,the aromatic compound$(s)$ is/are:

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