An aromatic compound A reacts with Zn/NH_4Cl, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of an aromatic nitro compound $(Ar-NO_2)$ with $Zn/NH_4Cl$ (a mild reducing agent) produces an aromatic hydroxylamine $(Ar-NHOH)$.$Ar

Vedclass · Accepted Answer

$-NO_2$

Vedclass · Answer

(B) The reaction of an aromatic nitro compound $(Ar-NO_2)$ with $Zn/NH_4Cl$ (a mild reducing agent) produces an aromatic hydroxylamine $(Ar-NHOH)$.$Ar-NO_2 + Zn/NH_4Cl \rightarrow Ar-NHOH + ZnO$$Ar-NHOH$ is a strong reducing agent that reduces Tollens' reagent (ammoniacal silver nitrate) to metallic silver $(Ag)$,which appears as a black precipitate.Therefore,the compound $A$ must contain a $-NO_2$ group.

An aromatic compound $A$ reacts with $Zn/NH_4Cl$,and the filtrate is then added to an ammoniacal silver nitrate solution,resulting in a black precipitate. Which group does compound $A$ contain?

Similar Questions

When $HNO_3$ is dropped onto the palm and washed with water,the skin turns yellow. This indicates the presence of:

$A$ positive carbylamine test is given by

Which of the following does $NOT$ give carbylamine test?

In the carbylamine test for primary amines,the resulting foul-smelling product is:

Assertion: Benzene diazonium chloride does not give a test for nitrogen.
Reason: Loss of $N_2$ gas takes place during heating.

Vedclass Test Series

Exam Paper Generator

Online Exam Module