Nitration of toluene is followed by reduction | vedclass

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(C) $1$. Nitration of toluene $(C_6H_5CH_3)$ gives a mixture of $o-$ and $p-$ nitrotoluene.$2$. Reduction of these nitro compounds with $Sn + HCl$ con

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Mixture of $o-$ and $p-$ bromotoluene

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(C) $1$. Nitration of toluene $(C_6H_5CH_3)$ gives a mixture of $o-$ and $p-$ nitrotoluene.$2$. Reduction of these nitro compounds with $Sn + HCl$ converts the $-NO_2$ group to $-NH_2$,yielding $o-$ and $p-$ toluidine.$3$. Diazotization of $o-$ and $p-$ toluidine with $NaNO_2 + HCl$ at $0-5 \ ^\circ C$ gives the corresponding diazonium salts.$4$. Heating these diazonium salts with $Cu_2Br_2 + HBr$ (Sandmeyer reaction) replaces the $-N_2^+Cl^-$ group with $-Br$.$5$. The final products are $o-$ and $p-$ bromotoluene.

Nitration of toluene is followed by reduction with $Sn + HCl$. The product obtained is then subjected to diazotization followed by heating with $Cu_2Br_2 + HBr$. What is the final product?

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