What is the product obtained when the product of alkaline hydrolysis of $C_2H_5 - N = C = O$ is reacted with $t$-butyl magnesium bromide?

Identify $C$ in the following reaction sequence:
$Cyclohexanone$ $\xrightarrow[\text{Alkaline medium}]{HCN} A$ $\xrightarrow{LiAlH_4} B$ $\xrightarrow{NaNO_2/HCl} C$

$Ph-NH_2$ $\xrightarrow{CH_3Cl \ (2 \ mole)} (A)$ $\xrightarrow{Ph-N_2^+ Cl^-} (B) \ (\text{major})$
Butter yellow is the product of the above reaction.

Ethylamine can be obtained by the:

$A$ nitrile $X$ is treated with $LiAlH_{4}$ to obtain compound $Y$ $(C_{2}H_{7}N)$. In a separate reaction,$X$ is hydrolyzed in an acidic medium to obtain $Z$. The product obtained after mixing $Y$ and $Z$ will be:

$STATEMENT-1$: Aniline on reaction with $NaNO_2 / HCl$ at $0^{\circ} C$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate.
$STATEMENT-2$: The colour of the compound formed in the reaction of aniline with $NaNO_2 / HCl$ at $0^{\circ} C$ followed by coupling with $\beta$-naphthol is due to the extended conjugation.