Which of the following is the correct decreas | vedclass

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(B) The basic strength of amines depends on the availability of the lone pair on the nitrogen atom and the stability of the conjugate acid formed.$1$.

Vedclass · Accepted Answer

$C_2H_5NH_2 > CH_3NH_2 > NH_3 > C_6H_5NH_2$

Vedclass · Answer

(B) The basic strength of amines depends on the availability of the lone pair on the nitrogen atom and the stability of the conjugate acid formed.$1$. $C_2H_5NH_2$ (Ethylamine) is a stronger base than $CH_3NH_2$ (Methylamine) due to the greater $+I$ effect of the ethyl group compared to the methyl group.$2$. Both aliphatic amines are stronger bases than $NH_3$ because the alkyl groups increase the electron density on the nitrogen atom.$3$. $C_6H_5NH_2$ (Aniline) is the weakest base because the lone pair on the nitrogen atom is involved in resonance with the benzene ring,making it less available for protonation.Therefore,the correct decreasing order is $C_2H_5NH_2 > CH_3NH_2 > NH_3 > C_6H_5NH_2$.

Which of the following is the correct decreasing order of basic strength for the given amines and ammonia?

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