A xrightarrow{H_2NOH} B xrightarrow{text{redu | vedclass

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Question

(D) The reaction sequence is as follows:$1$. $A$ reacts with hydroxylamine $(H_2NOH)$ to form an oxime $(B)$.$2$. The reduction of oxime $(B)$ yields

Vedclass · Accepted Answer

Acetaldehyde,Ethylamine

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(D) The reaction sequence is as follows:$1$. $A$ reacts with hydroxylamine $(H_2NOH)$ to form an oxime $(B)$.$2$. The reduction of oxime $(B)$ yields a primary amine $(C)$.$3$. The primary amine $(C)$ reacts with nitrosyl chloride $(NOCl)$ to form an alkyl chloride $(CH_3CH_2Cl)$.Given the final product is $CH_3CH_2Cl$ (ethyl chloride),the primary amine $(C)$ must be ethylamine $(CH_3CH_2NH_2)$.Working backwards:- $C$ is $CH_3CH_2NH_2$ (ethylamine).- $B$ is $CH_3CH=NOH$ (acetaldoxime).- $A$ is $CH_3CHO$ (acetaldehyde/ethanal).Thus,$A$ is acetaldehyde and $C$ is ethylamine.

$A$ $\xrightarrow{H_2NOH} B$ $\xrightarrow{\text{reduction}} C$ $\xrightarrow{NOCl} CH_3CH_2Cl$. What are $A$ and $C$ in the given reaction sequence?

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