What is the product formed when acetamide rea | vedclass

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(B) The reaction of acetamide $(CH_3CONH_2)$ with $NaOBr$ in an alkaline medium is known as the Hofmann bromamide degradation reaction.In this reactio

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$CH_3NH_2$

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(B) The reaction of acetamide $(CH_3CONH_2)$ with $NaOBr$ in an alkaline medium is known as the Hofmann bromamide degradation reaction.In this reaction,the amide group is converted into a primary amine with one carbon atom less than the original amide.$CH_3CONH_2 + NaOBr + 2NaOH \rightarrow CH_3NH_2 + Na_2CO_3 + NaBr + H_2O$.Thus,the product formed is methylamine $(CH_3NH_2)$.

What is the product formed when acetamide reacts with $NaOBr$ in an alkaline medium?

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