When a manganese (Mn^{II}) salt is fused with | vedclass

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(B) When $Mn^{II}$ salt is fused with $KNO_3$ and $NaOH$,it undergoes oxidation to form a manganate salt.The reaction is: $Mn^{2+} + 2NO_3^- + 4OH^- \

Vedclass · Accepted Answer

$+6$

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(B) When $Mn^{II}$ salt is fused with $KNO_3$ and $NaOH$,it undergoes oxidation to form a manganate salt.The reaction is: $Mn^{2+} + 2NO_3^- + 4OH^- \rightarrow MnO_4^{2-} + 2NO_2^- + 2H_2O$.In the product $MnO_4^{2-}$ (manganate ion),let the oxidation state of $Mn$ be $x$.$x + 4(-2) = -2 \implies x - 8 = -2 \implies x = +6$.Thus,the oxidation state of $Mn$ changes from $+2$ to $+6$.

When a manganese $(Mn^{II})$ salt is fused with a mixture of $KNO_3$ and solid $NaOH$,what will be the oxidation state of $Mn$ after it changes from $+2$?

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