When Lanthanoids $(Ln)$ react with oxygen $(O_2)$,what is the product $X$?

  • A
    $X = LnO_3$
  • B
    $X = Ln_2O$
  • C
    $X = Ln_2O_3$
  • D
    $X = LnO_2$

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$(b)$ All actinoid elements have a $7s^0$ configuration.
$(c)$ There are no electrons in the $7s$ orbital of actinoids.

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More number of oxidation states are exhibited by the actinoids than by the lanthanoids. The main reason for this is

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