(D) Paramagnetism is a property of substances that are attracted by a magnetic field. This property arises due to the presence of one or more unpaired

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They contain one or more unpaired electrons

(D) Paramagnetism is a property of substances that are attracted by a magnetic field. This property arises due to the presence of one or more unpaired electrons in the $d-$ orbitals of the metal ions. Since $3d-$ metal ions often have unpaired electrons in their $d-$ subshell,they exhibit paramagnetic behavior.

Class 12 Chemistry d-and f-Block Elements General Characteristics

Easy

$3d-$ metal ions exhibit paramagnetic behavior because . . . . .

A
Variable oxidation states
B
High electronegativity
C
High charge/size ratio and empty $d-$ orbitals
D
They contain one or more unpaired electrons

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Class 12 Questions

Class 12

Chemistry Questions

Chapter

d-and f-Block Elements

Subtopic

General Characteristics

Elements which generally exhibit multiple oxidation states and whose ions are usually coloured are

Easy

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In which one of the following pairs,both the elements do not have $(n-1)d^{10}ns^2$ configuration in their elementary state?

EasyKCET 2023

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Which of the following ions is diamagnetic?

Easy

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Assertion: Cuprous ion $(Cu^{+})$ has unpaired electrons while cupric ion $(Cu^{2+})$ does not.
Reason: Cuprous ion $(Cu^{+})$ is colourless whereas cupric ion $(Cu^{2+})$ is blue in the aqueous solution.

EasyAIIMS 2002

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The basic character of the transition metal monoxides follows the order
(Atomic no. $Ti = 22, V = 23, Cr = 24, Fe = 26$)

MediumAIPMT 2003

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$3d-$ metal ions exhibit paramagnetic behavior because . . . . .

Similar Questions

Elements which generally exhibit multiple oxidation states and whose ions are usually coloured are

In which one of the following pairs,both the elements do not have $(n-1)d^{10}ns^2$ configuration in their elementary state?

Which of the following ions is diamagnetic?

Assertion: Cuprous ion $(Cu^{+})$ has unpaired electrons while cupric ion $(Cu^{2+})$ does not.Reason: Cuprous ion $(Cu^{+})$ is colourless whereas cupric ion $(Cu^{2+})$ is blue in the aqueous solution.

The basic character of the transition metal monoxides follows the order(Atomic no. $Ti = 22, V = 23, Cr = 24, Fe = 26$)

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Assertion: Cuprous ion $(Cu^{+})$ has unpaired electrons while cupric ion $(Cu^{2+})$ does not.
Reason: Cuprous ion $(Cu^{+})$ is colourless whereas cupric ion $(Cu^{2+})$ is blue in the aqueous solution.

The basic character of the transition metal monoxides follows the order
(Atomic no. $Ti = 22, V = 23, Cr = 24, Fe = 26$)